Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Given that the temperature coefficient for the saponification of ethyl acetate by NaOH is 1.75.
Calculate the activation energy.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. Given, 
T 1 = 25º C = 25 + 273 = 298 K, T 2 = 35ºC = 35 + 273 = 308 K
(since, temperature coefficient is ratio of rate constants at 35ºC and 25º C respectively.)
2.303 log 10 
∴ 2.303 log 10
1.75 = 
∴ E a = 
Ea = 10.207 kcal mol –1
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